Question

Determine k so that (3k – 2), (4k – 6) and (k+2) are three consecutive
terms of an AP.​

Answer 1

Answer:

Step-by-step explanation:

(4k-6)-(3k-2)=(k+2)-(4k-6)

4k-6-3k+2=k+2-4k+6

K-4=-3k+8

K+3k=8+4

4k=12

K=3