Question

Determine k so that 3k-2,4k-6 and k+2 are three consecutive terms of an A. P.

Answer 1

As we know that... B=A+C/2
SO, A=3K-2
B=4K-6
C=K+2
THEREFORE, 4K-6=3K-2+K+2/2
=4K-6=4K-4/2
=8K-12=4K-4
=8K-12-4K-4=0
=4K-8=0
; = 4K=8
K=8/4
2.
.
.Hence, value of k is 2..