Math, asked by rohan685, 8 months ago

Determine k so that 4k + 8, 2k2 + 3k + 6 and 3k2 +4k + 4 are the three-consecutive term of an A.P.

Answers

Answered by jothika132002

3

Step-by-step explanation:

then 2b=a+c

So, 2(2k

2

+3k+6)=k

2

+4k+8+3k

2

+4k+4

4k

2

+6k+12=4k

2

+8k+12

6k=8k

∴k=0

Answered by danishjibran

2

Hope this answers the question

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