Question

Determine k so that k + 2 , 4 k+ 6 and 3k – 2 are three consecutive terms of an AP.​

Answer 1

Answer:

-3

Step-by-step explanation:

If k+2, 4k+6 and 3k-2 are three consecutive terms of AP.

so there common difference should be same

(4k+6)-(k+2)= (3k-2)-(4k+6)

3k+4 = -k-8

4k = -12

k = -3.

Hope you understand it........