Question

determine k so that k+2,4k-6,3k-2 are three consecutive terms of an AP
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Answer 1

value of K is 3

hope it helps you::)

Answer 2

Step-by-step explanation:

(k+2)+(3k−2)=2(4k−6)

⇒4k=8k−12

⇒4k−8k=−12

⇒−4k=−12

⇒4k=12

⇒k=

4

12

=3

Hence k=3.