Math, asked by mb7409471gmailcom, 8 months ago

Determine k so that k+2, 4k-6 and 3k-2 are three consecutive terms of an AP

Answers

Answered by aryan073

0

Step-by-step explanation:

4k-6-k-2

3k-8=0

k=8/3

Answered by sjishan650

0

Answer:

Given:( 3k-2), (4k-6) and (k+2) are three consecutive terms of an AP. Therefore answer the value of k is 7/2.

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