determine laurent series 1/z(z^2-3z+2) about z=0 for the region
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Answer:
f(z)=1z2−3z+2
=1(z−2)(z−1)=A(z−2)+B(z−1)
After finding common denominator, equating the numerators, and letting z=0, we get:
=1(z−2)(z−1)=1(z−2)+−1(z−1)
Letting w=z−2, we get:
f(w)=11−(−w+1)−11−(−w)
Step-by-step explanation:
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