determine lim x-π/2(tan3x/tanx)
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Answer:
The correct answer is 1/3.
Step-by-step explanation:
Let a = π/2 − x
lim(x→π/2) tan3x/tanx =lim(a→0) tan 3(π/2 − a) / tan (π2−a)
= lim(a→0) (1/tan3a) / (1/tana)
= lim(a→0) ( tan a / tan 3a )
= lim(a→0) (sin a * cos 3a) / (cos a * sin3a)
= lima→0 ( sina/a ) ( 3a/sin3a ) ( cos3a/a ) * 1/3
= 1 * (1) * (1/1) * (1/3) [ this is line number 6 ]
= 1/3
note: we know that
lim( x→ 0) sinx / x = 1
we just apply this technique in line number 6.
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