Question

Determine magnitude and direction of magnetic force on the particle when it moves in a uniform magnetic field 0.8T

Answer 1

Answer:

0.8qvsino' and direction of force depends on direction of velocity

Answer 2

Magnitude of force is 0.8 × qVsin(A)

Direction of force will be perpendicular to velocity & magnetic feild

•Force on a charge particle moving in a magnetic field

•lets say particle is moving with velocity V

• Magnetic feild B is plitted into two components i.e. BcosA & BsinA

where A is angle between B & V

•BcosA will not contribute towards force

•So Magnetic Force

F(m) = qV×B

i.e. F(m) = qVBsin(A)

•Direction of force :

1) Force is always perpendicular to velocity & magnetic feild

2) Particle under such force moves along circular path

•Magnitude of force

|F(m)| = qVBsin(A)

|F(m)| = 0.8 × qVsin(A)

•Direction of force depends upon direction of velocity