Question

Determine magnitude and directions of electric field,which would balance weight of proton,placed in electric field.
given:charge on each proton=1.6×10-19C,
acceleration due to gravity=10m/s2,mass of proton=1.6×10-27.​

Answer 1

Answer:

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Explanation:

ANSWER

To balance proton in electric field,

qE=mg (or) E= qmg=1.6×10 −19

1.7×10 −27×9.8=10×10 −8 =1×10 −7 V/m.