Determine n if ²nC3: nC3 = 12:1
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» 2nC3 : nC3 = 12 : 1
» [2n (2n - 1) (2n - 2)]/[1 × 2 × 3] ×
[1 × 2 × 3]/[(n (n - 1) (n - 2)] = 12
» 4 (2n - 1)/(n - 2) = 12
» 2n - 1 = 3n - 6
» n = 5
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