Question

Determine nature of roots of quadratic equation: x +2x9=0 Sol: Compare x +2x-9=0 with *************** a.. ,b2, C.. b-4ac=2-4 *... ,... =4-. +0 b4ac 0 Therefore the roots of the equation are .... ​

Answer 1

x²+2x-9=0........1

comparing eq 1 with ax²+bx +c=0

a= 1 , b= 2 and c= -9

Discriminant D

D= b²-4ac = 2²-4×1×-9 = 4+36 =40

here D is greater than 0

hence nature of roots of quadratic equation

is real and distinct roots