Question

Determine nature of roots of the quadratic equation 3y²-8y+2=0​

Answer 1

Answer:

3qube(3)

Step-by-step explanation:

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Answer 2

Answer:

3y2+8y+5=0

This equation comparing with ay2+by+c=0, we get

a=3,b=8,c=5

∴y=2a−b±b2−4ac

⇒y=2×3−8±64−4×3×5

⇒y=6−8±64−60

⇒y=6−8±2

Taking ′+′ sign, we get

thereforey=6−8+2=6−6=−1

Taking ′−′ sign, we get

∴y=6−8−2

=6−10

=3−5

Step-by-step explanation:

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