Determine oxidation no. Of Fe in Feso4(NH4)2.6H2O
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Oxidation no of SO4 is (-2)Oxidation no of NH4 is (+1)Water is eletrically neutal so 0FeSO4.(NH4)2.6H2O is not charged so sum(of oxidation no.) shud be equal to 0.x+(-2)+2(1)+6(0) equals 0 (repectively)So, xequals 0.so oxidation no. of Fe equals 0.
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