Determine P(A) for the set = {1,{2, 3}}
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In general, to find a power set, the easiest way is binary counting. What is this? The way to approach is, imagine you have n items to select. At any stage, you can choose to select an item - call it 1, or you choose not to - call it 0.
So, if you do not even want to select a single item, the choice will look:
000...000=0
n zeros.
You choose the first item, and nothing beyond:
000...001=1
n-1 zeros, followed by 1 : 1.
It is obvious that using n binary digits, we can generate 2n choices. Those choices, together, generates the power set.
In your case :
{1,{2},{3,4}}
000 → {}
001 → {1}
010 → { {2} }
011 → { 1, {2} }
…..
You got the idea.
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