Question

Determine P and Q

1)pq=32 and p+q=-12
pls answer me fast ​

Answer 1

Step-by-step explanation:

we can make and equation by considering these as a root

the equation is

x^2 + 12x + 32

Answer 2

Answer:

The value of p = 8 or 4 and q = 4 or 8 respectively.

Step-by-step explanation:

As per the question,

given is

p + q = 12 and pq = 32

Now the solution is,

pq = 32

$\Rightarrow q = \frac{32}{p}$

Substitute this value of q in p + q = 12

That is,

p + q =12

$\Rightarrow p + \frac{32}{p} =12$

$\Rightarrow p^{2}-12p+32=0$

$\Rightarrow (p-8)(p-4)=0$

That is $(p-8) =0$

or $(p-4) =0$

∴p = 8 or p = 4

When p = 8 ,

p + q = 12

⇒8 + q = 12

⇒q = 12 - 8

⇒q = 4

When p = 4,

p + q = 12

⇒4 + q = 12

⇒q = 12 - 4

⇒q = 8

Therefore, the value of p = 8 or 4 and q = 4 or 8 respectively.