Question

Determine ‘p’, if the line segment joining the points A(3, -2) and B(-6, p) is

perpendicular to Y-axis.​

Answer 1

Answer:

Answer is by using distance formula we get p=9

Step-by-step explanation:

Hope it helps you

Answer 2

Answer:

Step-by-step explanation:

Answer:

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Step-by-step explanation:

Answer:

I think this is FTB Question Paper

Answer is p = 6.

Step-by-step explanation:

Given :determine p if the line segments joining the points A(3,-2) and B(-6, p) is perpendicular to y-axis​.

Solution:

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A                                                                                         B

(3,-2)                                                                               (-6,P)

Given that the Line Segment AB is Perpendicular to Y  Axis then

the slope of the line AB = 0 (becaause if the line is perpendicular to y axis than the line segment lies on x axis.

                  We already know that the slope pf x -axis is 0 so

slope of the line segments joining the points A(3,-2) and B(-6, p) is

Using : Slope formula  $\frac{y_{2} - y_{1} }{x_{2} -x_{1} }$   = 0

Here y₁ = -2 , y₂ = p , x₁ = 3 , x₂ = -6

Substitute these Values in the Formula  $\frac{y_{2} - y_{1} }{x_{2} - x_{1} } = 0$

we get

                      $\frac{p-(-2)}{-6-(3)} = 0$

                   

                       $\frac{p+2}{-6-3} = 0$

                      $\frac{p+2}{-9} = 0$

               Cross multiplication we get

            $p +2 = 0$

      $p = 6$

∴ Therefore  the   value   of   p   in  which  the line segments joining the points A(3,-2) and B(-6, p) is perpendicular to y-axis​ is 2