Determine potential of a dipole at axial position
Answers
Answered by
0
please mark as brainleest
I have answered correctly
Attachments:
Answered by
0
the electric potential is 4πε01((r2−4a2)2P)
Explanation:
Let P be an axial point at distance r from the center of the dipole. Electric potential at point P is given as
V=V1+V2
V1and V2are the potentials at point P due to charges +q and –q respectively
V=4πε01(r−2aq+(r+2a−q))
V=4πε01((r2−4a2)4a)
V=4πε01((r2−4a2)2P)
Hence, the electric potential is 4πε01((r2−4a2)2P)
Similar questions