Math, asked by Molly3736, 10 months ago

Determine rational number x and y 4+√2/2+√2 =x-√y

Answers

Answered by krishnavamsi295
7

Answer:

x= 3 and y = 2

Step-by-step explanation:

4+√2/2+√2 =x-√y

=> x-√y = 4+√2/2+√2 x 2 - √2 / 2 - √2

=> x-√y = (4+√2)(2-√2)/ (4 -2)       (a+b)(a-b) = a^2- b^2

=> x-√y = (6-2√2)/ 2

= x-√y = 3 - √2

Answered by amitnrw
6

Given : 4+√2/2+√2 = x-√y​

To Find : rational numbers x and y

Solution:

4+√2/2+√2 = x-√y​

LHS = (4 + √2)/(2+ √2)

Multiply and divide by 2 - √2

=  (4 + √2)(2 - √2) / (2 + √2)(2 -√2)

= (8  - 4√2 + 2√2  - 2) /(4 - 2)

= (6  - 2√2)/2

= 3 - √2

comparing with

x - √y​

x = 3

y = 2

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