Question

Determine real values of x and y for which each statment is true (x-yi)= 2+I/1+I

Answer 1

Answer:

(i)

(2+3i)x2−(3−2i)y=2x−3y+5i

(2x2−3y)+(3x2+2y)i=2x−3y+5i

[2x2−3y=2x−3y3x2+2y=5]

solving the above 2 equations, we get,

[2x2−3y=2x−3y3x2+2y=5]⇒(x=0,x=1,y=25y=1)

(ii)

4x2+3xy+(2xy−3x2)i=4y2−2x2+(3xy−2y2)i

8x2+6xy+2i(2xy−3x2)=8y2−x2+2i(3xy−2y

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

$\frac{2+i}{1+i} \\\frac{2+i}{1+i} X\frac{1-i}{1-i} \\\frac{(2+i)(1-i)}{(1+i)(1-i)} \\\frac{2-2i+i-i^{2} }{1^{2} -i^{2} } \\\frac{2-i-(-1)}{1-(-1)} \\\frac{3-i}{2} \\\frac{3}{2} -\frac{i}{2}$

compare with x-yi

$x=\frac{3}{2} \\y=\frac{1}{2}$