Determine resultant force acting on charge Q = 3 4 microcoulomb at point C
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Answer :
The forces are as shown in ANS. Figure.
F
1
=
r
12
2
k
e
q
1
q
2
=(8.99×10
9
C
2
N.m
2
)=
(3.00×10
−2
m)
2
(6.00×10
−6
C)(1.50×10
−6
C)
=89.9N
F
2
=
r
13
2
k
e
q
1
∣q
3
∣
=(8.99×10
9
C
2
N.m
2
)=
(5.00×10
−2
m)
2
(6.00×10
−6
C)(2.00×10
−6
C)
=43.2N
F
3
=
r
23
2
k
e
q
2
∣q
3
∣
=(8.99×10
9
C
2
N.m
2
)=
(2.00×10
−2
m)
2
(1.50×10
−6
C)(2.00×10
−6
C)
=67.4N
(a) The net force on the 6μC charge is
F
(6μC)
=F
1
−F
2
=
46.7Ntotheleft
(b) The net force on the 1.5μC charge is
F
(1.5μC)
=F
1
+F
3
=
157Ntotheright
(c) The net force on the −2μC charge is
F
(−2μC)
=F
2
+F
3
=
111Ntotheleft
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