Determine s so that s² + 4s + 8, 2s² + 3s + 6, 3s² + 4s + 12 are 3 consecutive terms of an A.P.
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First term + third term = 2(second term)
Use this ( it applies in all AP)
So (s^2+4s+8)+(3s^2+4s+12)=2(2s^2+3s+6)
=> 8s+20=6s+12
=>2s=-8
=>s=-4
Use this ( it applies in all AP)
So (s^2+4s+8)+(3s^2+4s+12)=2(2s^2+3s+6)
=> 8s+20=6s+12
=>2s=-8
=>s=-4
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