Determine such that
A = 2 i + ſ + k and B = 4 î - 2j-2 k
are perpendicular to each other.
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Explanation:
If two vectors are perpendicular then their scalar product is zero.
As A.B= |A|×|B|×Cos(theta)
When theta is 90° then Cos(theta) is zero hence scalar product of two perpendicular vectors is zero.
A=2i+xj+k [I think here the variable is given which needs to be found]
B=4i-2j-2k
A.B= (2×4) + (X×(-2)) + (1×(-2))
=>A.B=8-2x-2=0
=>2X=6
=>x=3
So A=2i+3j+k
So u just need to prove the scalar product to be zero, but I think u missed some part in the question, I hope you got the concept.
Hope it helps...
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