Physics, asked by nurainanasar1, 7 months ago

Determine such that
A = 2 i + ſ + k and B = 4 î - 2j-2 k
are perpendicular to each other.​

Answers

Answered by akamran2301
1

Explanation:

If two vectors are perpendicular then their scalar product is zero.

As A.B= |A|×|B|×Cos(theta)

When theta is 90° then Cos(theta) is zero hence scalar product of two perpendicular vectors is zero.

A=2i+xj+k [I think here the variable is given which needs to be found]

B=4i-2j-2k

A.B= (2×4) + (X×(-2)) + (1×(-2))

=>A.B=8-2x-2=0

=>2X=6

=>x=3

So A=2i+3j+k

So u just need to prove the scalar product to be zero, but I think u missed some part in the question, I hope you got the concept.

Hope it helps...

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