Determine term of an AP whose 9th term is -10 and common difference is 5/4
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Determine 27th term of an AP whose 9th term is -10 and common difference is 5/4
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Answered by
3
given a₉ = -10 ; d = 5/4
a+ 8d = -10
a + 8(5/4) = -10
a + 2(5) = -10
a + 10 = -10
a = -10-10
a = -20
a₂₇ = a + (n-1)d
a₂₇ = -20 +(27-1) 5/4
= -20 + 26 (5/4)
= -20 + 13(5/2)
= -20 + 65/2
= -40+65/2
= 25/2
a₂₇= 12.2
a+ 8d = -10
a + 8(5/4) = -10
a + 2(5) = -10
a + 10 = -10
a = -10-10
a = -20
a₂₇ = a + (n-1)d
a₂₇ = -20 +(27-1) 5/4
= -20 + 26 (5/4)
= -20 + 13(5/2)
= -20 + 65/2
= -40+65/2
= 25/2
a₂₇= 12.2
Answered by
2
a=a9-8(d),
a= -10-8(5/4)=-10-10=-20
a=-20.
thn,a27=a+(n-1)d
=-20+(27-1)5/4
=-20+26*5/4
=-20+130/4
=-80/4+130/4
=50/4
=12.5
27th term of the AP is 12.5
a= -10-8(5/4)=-10-10=-20
a=-20.
thn,a27=a+(n-1)d
=-20+(27-1)5/4
=-20+26*5/4
=-20+130/4
=-80/4+130/4
=50/4
=12.5
27th term of the AP is 12.5
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