Math, asked by rapperboy, 1 year ago

Determine term of an AP whose 9th term is -10 and common difference is 5/4


rapperboy: Determine 27th term of an AP whose 9th term is -10 and common difference is 5/4
rapperboy: the answer is 45/2
rapperboy: kindly show steps
durkeshbarath: sry!i didn't see the -ve symbol
TPS: answer is 12.5

Answers

Answered by bhaghi
3
given a₉ = -10 ; d = 5/4
   a+ 8d = -10
  a + 8(5/4) = -10
   a + 2(5) = -10
  a + 10 = -10
a = -10-10
 a = -20
a₂₇ = a + (n-1)d
a₂₇ = -20 +(27-1) 5/4
     = -20 + 26 (5/4)
     = -20 + 13(5/2)
     = -20 + 65/2
     = -40+65/2
     = 25/2
 a₂₇= 12.2

bhaghi: pls mark as best....
rapperboy: the answer is 22.5
bhaghi: thanQ 4 marking best.........
Answered by durkeshbarath
2
a=a9-8(d),
a= -10-8(5/4)=-10-10=-20
a=-20.
thn,a27=a+(n-1)d
           =-20+(27-1)5/4
           =-20+26*5/4
            =-20+130/4
           =-80/4+130/4
            =50/4
            =12.5
27th term of the AP is 12.5


rapperboy: 22.5 is the answer
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