Question

Determine tha value of a for which the polynomial 2x^4-ax^3+4x^2+1

Answer 1

Step-by-step explanation:

We have

=> 2x4 - ax³ + 4x² + 2x + 1 = p(x)

Thus for the divisiblity of 1 - 2x

=> 1-2x = 0

=> x = 1/2

Thus P(1/2) = 0

=> 2(1/2)* -a(1/2)³ + 4(1/2)² + 2(1/2) + 1 = 0

=> 2(1/16) - a(1/8) + 4(1/4) + 1 + 1 = 0

=> 1/8 - a/8 +1+1+1=0

=> 1/8-a/8 + 3 = 0

=> a/8 = 25/8

=> a = 25

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