Determine the 10th term from the end of the ap 4,9,14.........254
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This is quite simple:
The formula needed here is: a(n)=a-(n-1)d
Step-by-step explanation:
ATQ, first term (a)= 4, common difference (d)=5 & last term (x) = 254., required term (f)=?
=> a(n)=a-(n-1)d.
Substitute known values ,
a(f)= 254-(10-1)5
a(f)= 254-9(5)
a(f)= 254-45
a(f)=209.
Thus required term is 209.
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