Determine the 10th term of a GP. whose 5th term is 16 and common ratio is -2.
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Answer:
6
Step-by-step explanation:
given
common difference (d)= –2
a +4d= 16
a+4(–2)= 16
a= 24
n= 10
an=?
an= a + (n–1)d
24 + 9×–2
6
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