determine the 10th term of Ap 2.7.12
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2,7,12
a = 2
d = 7 - 2 = 5
a10 = a + 9d = 2 + 9(5) = 2 + 45 = 47
So, 10 th term is 47
a = 2
d = 7 - 2 = 5
a10 = a + 9d = 2 + 9(5) = 2 + 45 = 47
So, 10 th term is 47
ramansirji111:
a=2 and a2 =7 d=5 so now we can find a10 by a10=a+9d we get ans as47
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the 10 th term of AP is 47
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