Determine the 1st term of an Arithmetic sequence of Tk=2×3k
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Answer:
put k=1
t1= 6
I hope it would help you
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T1 = 6 of an Arithmetic sequence of Tk=2×3k
Step-by-step explanation:
Tk = 2 * 3k
putting k = 1
T1 = 2 * 3(1)
=> T1 = 2 * 3
=> T1 = 6
T2 = 2 * 3(2) = 12
T3 = 2 * 3(3) = 18
Common difference = 6
AP is 6 , 12 , 18 .................
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