Determine the 25 th term of an A.P ;whose9th term is _6 and common difference 5by 4
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a9 = 6
D = 5/4
so,
a + 8d = 6
a + 8(5/4)=6
a + 10 = 6
a = 6-10
a= -4
hence
a=-4 , d=5/4. n=25
we have to find 25th term
a+(n-1)d = an
-4+(25-1)5/4= a25
-4+ 30
a25= 26
Answered by
0
given
a9 = -6
a25 =?
d= 5
a 25 = a+24 d
= a+ 24*5 = 120
a= -120
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