Determine the A.P. whose 3rd term is 17 and 6th term exceeds the 4th term by 12.
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Answer:
the A.P is 5,11,17 ,23,29,35......
Step-by-step explanation:
according to question ,
a+2d=17→ 1
and a+5d=a+3d+12→ 2
2d=12 [by simplifying equation 2 ]
d=6
and substituting d=6 in equation 1
a=5
and by using a= 5 and d=6 you will get the A.P
thank you
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