Question

Determine the A.P whose 4th term is 17 and the 10th term exceeds the 7th term by 12​

Answer 1

a=17

a10=a7 +12

a+9d=a+6d+12

3d=12

d=4

a4=17

a+3d=17

put d=4

a+3×5=17

a +12=17a=5

ap:5,9,13,17

Answer 2

AP:5,9,13......

Step-by-step explanation:

Formula of nth term : $a_n=a+(n-1)d$

Substitute n = 4

$a_4=a+(4-1)d=a+3d$

We are given that 4th term is 17

$a+3d=17$------1

We are given that 10th term exceeds the 7th term by 12​

$a+(10-1)d-(a+(7-1)d)=12\\a+9d-a-6d=12\\3d=12\\d=4$

Substitute value of d in 1

a+3(4)=17

a+12=17

a=5

So, AP : 5,5+4,5+4+4,....

AP:5,9,13......

#Learn more:

Determine the A.P. whose third term is 16 and the 7th term exceeds the 5th term by 12.​

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