Math, asked by santhalingam2005, 5 months ago

Determine the A.P. whose third term is 16 and 7th term exceeds the
5th term by 12.please show the method it's urgent

Answers

Answered by shilshaurya5606
2

Answer:

4, 10, 16, 22, 28...

Step-by-step explanation:

Third term = a + (3 - 1)d => a + 2d = 16

Fifth term = a + (5 - 1)d => a + 4d

Seventh term = a + (7 - 1)d => a + 6d

Acc. to ques, a + 4d + 12 = a + 6d

=> 12 = a + 6d - (a + 4d)

=> 12 = a + 6d - a - 4d

=> 12 = 2d

∴ d = 12/2 => 6

We can find the second term by subtracting d from third term.

=> Second term = 16 - 6 => 10

∴ First term = 10 - 6 => 4

Thus, the AP is 4, 10, 16, 22, 28...

Answered by ana205
1

Answer:

The A.P will be 4, 10, 16, 22, 28...

Step-by-step explanation:

refer the attachment below for your answer

hope it helps

ana205

Attachments:
Similar questions