Determine the A.P. whose third term is 16 and 7th term exceeds the
5th term by 12.please show the method it's urgent
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Answered by
2
Answer:
4, 10, 16, 22, 28...
Step-by-step explanation:
Third term = a + (3 - 1)d => a + 2d = 16
Fifth term = a + (5 - 1)d => a + 4d
Seventh term = a + (7 - 1)d => a + 6d
Acc. to ques, a + 4d + 12 = a + 6d
=> 12 = a + 6d - (a + 4d)
=> 12 = a + 6d - a - 4d
=> 12 = 2d
∴ d = 12/2 => 6
We can find the second term by subtracting d from third term.
=> Second term = 16 - 6 => 10
∴ First term = 10 - 6 => 4
Thus, the AP is 4, 10, 16, 22, 28...
Answered by
1
Answer:
The A.P will be 4, 10, 16, 22, 28...
Step-by-step explanation:
refer the attachment below for your answer
hope it helps
ana205
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