Math, asked by santhalingam2005, 5 months ago

Determine the A.P. whose third term is 16 and 7th term exceeds the
5th term by 12.please show the method it's urgent

Answers

Answered by rushikvadher
1

Answer:

Yes It Is An A.P

4,10,16,22,28,34,40.

a=4,d=6

Step-by-step explanation:

t7th = t5th + 12

a+6d=a+4d+12

6d-4d=12

2d=12

d=6.

t3th = 16

a+2(d)=16

a+2(6)=16

a=16-12

a=4.

Answered by ishaanpearl0922
1

Answer:

The answer is 4, 10, 16, 22,......

Step-by-step explanation:

Since the third term is given to us as 16,

=> a+2d = 16 (An = a+(n-1)d) ....(1)

Also, the difference between the 7th term and the 5th term is 12

So,

a + 6d - (a + 4d) = 12

a + 6d - a - 4d = 12

2d = 12

d = 6

Now putting d = 6 in (1)

a + 12 = 16

a = 4

So the AP becomes 4, 10(4+6), 16(4 + 6×2) , 22 and so on

Similar questions