determine the acceleration of a proton in an electric field of intensity of 100N/C. how many times this acceleration is greater than acceleration due to gravity? Given mass of proton is 1.6*10^-27 Kg.
Answers
Answer:
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The acceleration of a proton is 10^10 m/s² and it is 10^9 times greater than the acceleration due to gravity.
Given: An electric field of the intensity of 100 N/C. The mass of a proton is 1.6*10^-27 Kg.
To Find: The acceleration of a proton and how many times this acceleration is greater than the acceleration due to gravity?
Solution:
We know that the acceleration of a proton can be calculated using the formula,
acceleration (a) = qE / m ...(1)
where, q = charge, E = Electric field, m = mass of charged particle.
Coming to the numerical, we are given E = 100 N/C, m = 1.6 × 10^-27 Kg,
q = 1.6 × 10^-19 C
Putting respective values in (1), we get,
acceleration (a) = qE / m
⇒ a = ( 1.6 × 10^-19 × 100 ) / ( 1.6 × 10^-27 )
⇒ a = 10^10 m/s²
We know that the acceleration due to gravity is 10 m/s².
So, the number of times 'a' is greater = 10^10 / 10
= 10^9
Hence, the acceleration of a proton is 10^10 m/s² and it is 10^9 times greater than the acceleration due to gravity.
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