Question

determine the acceleration that occurs when 12 N net force is applied to 3kg object

Answer 1

Answer:

the acceleration of the second object is a=2 m/s2 a = 2 m/ s 2 .

Answer 2

Explanation:

F(net) = m.a

12N = 3kg × a

a = 12/3

=> a = 4m/s^2