Question

determine the acceleration that result when a 12-N net force is applied to a 3kg object and to a 6 kg object​

Answer 1

Answer:

object 1 = 4

object 2=2

Step-by-step explanation:

f=m X a

f/m =a

Answer 2

Answer:

Case 1 :5 m/s²

Case 2 :2.5 m/s²

Step-by-step explanation:

Case 1 :When a 15N net force is applied to a 3kg object

Mass(m)=3kg

Force(f)=15N

Acceleration (a)=?

F=m×a

15=3×a

a=5 m/s²

Case 2: When a 15N net force is applied to a 6kg object

Mass(m)=6kg

Force(f)=15 N

Acceleration(a)=?

F=m×a

15=6×a

a=2.5m/s²

A 3-kg object experiences an accelerartion of 5m/s².

A 6-kg object experiences an accelerartion

of 2.5m/s².

Hope its helpful.