Determine the acceleration that result when a 12-N net force is applied to a 3-kg object and then to a 6-kg object.
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Answer:
a in first case=4m/sec²
a in second case=2m/sec²
Explanation:
a¹= F/m¹
=12/3
=4 m/sec²
a²= F/m²
= 12/6
= 2 m/sec²
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