Question

Determine the amount of CaCl2 (i = 2.47) dissolved in 2.5 litre of water such that its osmotic pressure is 0.75 atm at 27°C.​

Answer 1

Answer:

3.399 gram

Explanation:

osmotic pressure= i *M *R *Tk

0.75= 2.47* Molarity* 0.0826* (27+273)

molarity= moles/ volume

mole= mass/ molar mass

molar mass = 40+35.5*2= 111

molarity= 0.0122 = (mass/111) /2.5

mass= 3.39 gram