Question

Determine the amount of charge stored on either plate of a capacitor (4x10-6 F) when connected across a 12 volt battery.​

Answer 1

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@ngel..!

Answer 2

Given: A capacitor (4x10⁻⁶ F) is connected across a 12 volt battery.​

To find: The amount of charge stored on either plate of the capacitor.

Solution:

• The capacitance of a conductor is a measure of its ability to hold electric current.
• If a charge raises the potential of a conductor, then the charge is directly proportional to the potential of the conductor.

        $Q \alpha V$

• Here, Q is the charge and V is the potential of the conductor.
• To equate to charge and the potential, a constant depending upon the size and shape of the conductor is introduced.

        $Q = C V$

• Here, C is the constant and is called the capacitance of the conductor.

        $Q = 4 * 10^{-6}F * 12V$

            $= 4.8 * 10^{-5} C$

Therefore, the amount of charge stored on either plate of the capacitor is 4.8×10⁻⁵ C.