Question

Determine the angular acceleration of a rotating body which slows down from 500 rpm to rest in 10 seconds

Answer 1

Explanation:

N=500 rpm

so angular velocity = 2πN/60= 1000π/60= 50π/3 radians/sec

Now using motion of equations for circular motion

ang vel = ang acceleration * time

=> ang acceleration = 5π/3 radian/sec2

Answer 2

Answer:

5 π / 3 rad / sec²

Explanation:

Given :

ω = 500 rpm

ω in term of rad / sec

= > ω = 500 × 2 π / 60 rad / sec

= > ω = 50 π / 3 rad / sec

Time t = 10 sec

We have to find angular acceleration α :

We know :

α = ω / t

Putting value here we get :

= > α = ( 50 π / 3 ) / 10 rad /sec²

= > α = 5 π / 3 rad / sec²

Hence we get required answer!