Determine the angular acceleration
of rotating body which slows down
from 500 r.p.m to rest in
10 second.
Answers
Answered by
8
use third law of equation ( in rotational motion)
Answered by
11
Change in angular velocity = 0- 500 = -500rpm = -500×2π/60 = -50π/3 rad/s
Time = 10 secs
Angular acceleration = -5π/3 rad/s^2
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