determine the AP that has 17th term as 4 and 15th term has 36
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Answer:
⇒a
n
=a+(n−1)d
⇒a
17
=a+16d....(1)
⇒a
10
=a+9d.....(2)
⇒a
17
−a
10
=7
⇒(a+16d)−(a+9d)=7
⇒7d=7
⇒
d=1
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