determine the Ap whise 3rd term is 16 and 7th term exceeds the 5th term by12
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Let a be the first term of AP.
Third term = a + 2d = 16 -----1
seventh term = fifth term + 12
a + 6d = a + 4d + 12
6d - 4d = 12
2d = 12
d = 12/2
d = 6
put value of d in eqn.1
a + 2(6) = 16
a + 12 = 16
a = 16 - 12
a = 4
AP = a, a+d, a+2d,.....
= 4, 10, 16,.....
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