Determine the Ap whose 2nd term 13 and 5th term 24
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a2=== a+d=13
a5=== a+4d=24
on equating a+d=13
a+4d= 24
on subtracting A gets cancelled
u get= -3d =-11
d=11/3
substituting d value in eq-1
11/3 +d= 13
d=39/3 - 11/3
d=28/3
a5=== a+4d=24
on equating a+d=13
a+4d= 24
on subtracting A gets cancelled
u get= -3d =-11
d=11/3
substituting d value in eq-1
11/3 +d= 13
d=39/3 - 11/3
d=28/3
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