Question

.. Determine the AP whose 3rd term is 16 and 7th term exceeds 5th term by 12.

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Answer 1

Answer:

a3 =16

a7 = a5+12

a+6d = a+4d+12

2d = 12

d = 6

a3 = 16

a+2d = 16

a+2(6) = 16

a+12 = 16

a = 4

4,10,16,22-------

Answer 2

Answer:

$given\:a+2d = 16 \\ a+7d=a+5d + 12\\ 2d \: = 12 \\ d = 6 \\ a \: = 16 - 2d =16 -12=4 \\ a = 4$

a, a+ d, a+2d,a+3d

4,10,16,22...