Question

DETERMINE THE AP WHOSE 3RD TERM IS 16 AND WHEN 5TH TERM IS SUBRACTED FROM 7TH TERM WE GET 12

Answer 1

Answer:

let a be 1st term n d be the common difference

3rd term= a+2d=16

5th term= a+4d

7th term= a+6d

7th term - 5th term= 2d=12

=> d=6

hence a+2d=16

=> a=4

hence AP is 4, 10, 16, 22, 28, 34, 40

Step-by-step explanation: