Question

determine the AP whose 3rd term is 5 and the 7th term is 9 ?​

Answer 1

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Answer 2

Anjani2019

3rd term is 5 ,so a+(n-1)d => a + 2d = 5 ( eq 1)

7th term is 9 , so a+ (n-1)d => a+6d = 9  ( eq 2)

subtract eq 1 & 2

=> 4d = 4

d= 1

substitute d=1 in eq 1

a + 2d = 5

a+ 2* 1= 5

a= 5-2

a=3

a+d= 3+1=4

a+2d= 3+2*1= 5

a+3d = 3+3*1=6

then the AP is 3, 4, 5,6 ...................