Determine the AP whose 3rd term is 5 and the 7th term is 9
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an = a + (n-1) d
5 = a + ( 3 - 1) d ----- 1
9 = a + ( 7 - 1) d ------2
from 1 & 2
5 = a + 2d
9 = a + 6d
eliminating a
-4d = -4
d = 1
put in 1
5 = a + 2
a = 3
AP = 3, 4 (3+1) , 5(4+1) , 6, 7, 8, 9,.........
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