Question

Determine the AP whose 3rd term is 5 and the 7th term is 9.
​

Answer 1

Step-by-step explanation:

this is answer for your question hope you mark on brain list

Answer 2

Given :-

• Third term a3 = 5

• The seventh term a7 = 9

To Find:-

• To Detrrmine the Ap

Solution :-

We Know that an Ap is a sequence of numbers which has a same common difference d and has a first term a

• Here we should find out the Ap but some clues are given in the Question itself that we have said in the given session.

Now,

It is given that the third term = 5

so, lets start from that....

• a3 = a+2d [General form of an ap]

• => 5 = a+ 2d ------(1)

Now it is also given that the seventh term of the Ap is 9 let us state that....

• a7 = a+6d

• 9 = a+6d ------(2)

We have equations 1 and 2 Lets us solve

★5 = a+2d

★9 = a+6d

____________

= -4 = 0+-4d

» -4d = -4

» so, d = 1

• So we get d = 1 Substitute the value of d in equation 1

So, we get,

• 5 = a+2*1

• 5 = a + 2

• a = 3

Since a = 3 and d = 1 so, the ap is

$\sf{ \bold{ \underline{ \red{</strong></p><p><strong>A</strong><strong>p = 3</strong><strong>,</strong><strong>4</strong><strong>,</strong><strong>5</strong><strong>,</strong><strong>6</strong><strong>,</strong><strong>7</strong><strong>,</strong><strong>8</strong><strong>,</strong><strong>9</strong><strong>,</strong><strong>10}{} }{} }{} }{}$

★_____________________________★